CancelReport This Post

Please fill out the form below with your name, e-mail address and the reason(s) you wish to report this post.

 

Crossword Help Forum
Forum Rules

graham9perkins

22nd January 2026, 01:08
Well that was a challenge! I definitely needed the hint here about using the grid diagonal. Thanks to Wikipedia for listing the 1a 7a instances, only one of which fitted the diagonal length and presumed 55a 66a hint.
Did anyone discover a way to compute the cipher? Preamble WONDERFUL COMPUTABLE … seems to indicate there is an algorithm.
71 of 88  -   Report This Post

darla

22nd January 2026, 01:40
I think “wonderful computable algebraic formula” likely refers to the formula to find the area.
72 of 88  -   Report This Post

buzzb

22nd January 2026, 03:21
I doubt there is any way to compute the cipher especially since there are so many ambiguous unchecked cells.

As recommended earlier, you should use the fact that the resulting crossing entries are words or phrases or abbreviations (38a is problematic). In many cases there is only one possible letter to choose (you can assume that no letter decodes to itself) or just a couple. 19a is particularly good for this. That will establish a set of decodings that you can use for the other three edges.
73 of 88  -   Report This Post

iratus

22nd January 2026, 09:33
Start with the perimeter letters which occur checked more than once.
74 of 88  -   Report This Post

unstuck

22nd January 2026, 13:58
Many thanks Ozzy. I take it that there is no key which permits deciphering but simply random substitutions. And yes, the right-hand column was the give-away to completing the deciphering.
75 of 88  -   Report This Post

unstuck

22nd January 2026, 14:00
Many thanks Quisling, your comment confirming the two entries you refer to.
76 of 88  -   Report This Post

crowdedmorning

22nd January 2026, 19:34
Really struggling with this one for whatever reason—I have one initial clue left to solve, 13dn, which I can’t seem to figure out. I also have no clue how to tackle the cipher; it seems from responses in this thread that it’s not very difficult, which guess means I’m missing something obvious because I can’t figure out how to proceed with so many unchecked letters. Any help welcome!
77 of 88  -   Report This Post

crowdedmorning

22nd January 2026, 19:42
(Of course I immediately just solved 13dn. Still no clue how to proceed with endgame after a few days of staring.)
78 of 88  -   Report This Post

mack

22nd January 2026, 19:57
See posts 45, 52 and 75.
For example, 37d has only one possible substitution for the final letter.
79 of 88  -   Report This Post

smellyharry

22nd January 2026, 20:01
Remember that the crossing words have to be real words. And you can assume no letter will map to itself. That gives you very few options. There's only one option for the second letter of 13d for example. And often only 2 or 3 for others. Especially where the same letter appears several times in the perimeter (eg c).

80 of 88  -   Report This Post