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Thanks Dim. I believe 12a also works if you reverse the middle two digits (in the absence of knowing the other 6 digits answers). Which obviously gives you the same sum.

Hi. Listener crossswords normally much too hard for me to even understand instructions, but this one simple to understand for me. Nearly done, except like someone else, I have 3 possibilities for 15. What am I missing?
And why is one of 6 digit numbers obvious to get first? I seem to be missing something, but what. Any very subtle hint appreciated if allowed. Thanks

Think what others might be like the obvious one.

Sorry, timboh, I didn't read your message carefully enough before replying. When you were about 10 or so you discovered something interesting when you met division, and started dividing 1 by various things. Try recapturing that feeling.

If you search the internet for "cyclic numbers" you'll be shown something about a subset of the possible 6-digit entries.

Thanks Cockie. Very subtle I feel, & still beyond me at moment, but hopefully might suddenly hit me! But have manages 15 now, & 2 of unclued through trial & error. Maybe get there eventually! Cheers

Are the factors of the un-clued entries all prime numbers? At posts 30 and 31, it is suggested that the answer to 12 across has a digital sum of 33 and a digital product of 6048. I have identified a number which meets these criteria and If I arrange the digits as the next-to-lowest possible number, then its factors are prime. This then clashes with the final digits of my entries for 3 and 5 down. I feel as though I may have answered my own question: i.e. the factors of the unclued entries are not necessarily all prime, or are they?

Are the factors of the un-clued entries all prime numbers? At posts 30 and 31, it is suggested that the answer to 12 across has a digital sum of 33 and a digital product of 6048. I have identified a number which meets these criteria and If I arrange the digits as the next-to-lowest possible number, then its factors are prime. This then clashes with the final digits of my entries for 3 and 5 down. I feel as though I may have answered my own question: i.e. the factors of the unclued entries are not necessarily all prime, or are they?

Sorry, all. For some reason my message has appeared twice.

Er, if a number has three or more prime factors, then the product of any two of them in a non-prime ('composite') factor.