Question one is incomplete. The smallest right-angled
triangle which can be drawn with sides of three consecutive integers is 3, 4 & 5 which, as Philip wrote, has an area of 6 sq inches. However sides of 2, 3 & 4 will form the smallest triangle with sides of consecutive integer values.
The area of any triangle of sides a, b & c can quickly be calculated using Heron's formula:
A = SQRT(s * (s-a) * (s-b) * (s-c))
where s = (a + b + c)/2
So for the smallest possible triangle with sides of 2, 3 & 4 the area will be very slightly more than 2.9 sq inches.
Hope that keeps everyone happy!