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Sally was using a new word processing program to address invitations to four friends. After 6 attempts she printed out the results. The second line of each attempt had only two elements that were correct for that addressee. No two people's correct addresses had any of the same elements. The third element was part of the correct address of one of the other addressees. What is the actual address of each of the friends?

Miss N. Burgeon Ms. M. Blossom
611 Daisy Avenue 161 Lily Boulevard

Mrs. H. Bunch Miss N. Burgeon
116 Carnation Drive 116 Daisy Street

Mr. M. Bloom Mr. M. Bloom
166 Daisy Street 166 Camellia Boulevard


****This is so confusing to understand and solve...Anyone care to try it?***

Bloom 166 Camellia Street
Burgeon 116 Daisy Avenue
Bunch 161 Carnation Drive
Blossom 611 Lily Boulevard

Bloom has to live at 166 and Burgeon at Daisy

If Burgeon is at Daisy then Bloom must be at Camellia and as he can't now be Boulevard he is at Street.

If Burgeon isn't Street, she must be 116 and therefore at Daisy Avenue

etc etc etc

Hi, icauser!
It's quite logical if you think it through!