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You may have seen this, but if not I hope you like it. Please don't give the answer if you figure it out, to give other solvers a chance to think it through. Feel free to comment though. Will post the answer tonight.

(x-a)(x-b)(x-c)......(x-y)(x-z) = ?

It's not a problem, it is an evaluation. Hardly takes a lot to work out,

Naughty , very naughty !

like the pun

Bump

I guess the answer would be redundant!

No, please post the answer.

cloverjo: clue: Paul has cheekily omitted all the rest of the alphabet, including (x-x)

Oh gosh. I should have thought of that. Thanks, jazzgirl.

And for anyone who hadn't worked it out at the beginning..........Marty gave the game away with his comment in post 3!